Multiple reactions in vanadyl-V(IV) oxidation by H2O2

Oxidation of vanadyl sulfate by H₂O₂ involves multiple reactions at neutral pH conditions. The primary reaction was found to be oxidation of V(IV) to V(V) using 0.5 equivalent of H₂O₂, based on the loss of blue color and the visible spectrum. The loss of V(IV) and formation V(V) compounds were confirmed by ESR and⁵¹V-NMR spectra, respectively. In the presence of excess H₂O₂ (more than two equivalents), the V(V) was converted into diperoxovanadate, the major end-product of these reactions, identified by changes in absorbance in ultraviolet region and by the specific chemical shift in NMR spectrum. The stoichiometric studies on the H₂O₂ consumed in this reaction support the occurrence of reactions of two-electron oxidation followed by complexing two molecules of H₂O₂. Addition of a variety of compounds—Tris, ethanol, mannitol, benzoate, formate (hydroxyl radical quenching), histidine, imidazole (singlet oxygen quenching), and citrate—stimulated a secondary reaction of oxygen-consumption that also used V(IV) as the reducing source. This reaction requires concomitant oxidation of vanadyl by H₂O₂, favoured at low H₂O₂:V(IV) ratio. Another secondary reaction of oxygen release was found to occur during vanadyl oxidation by H₂O₂ in acidic medium in which the end-product was not diperoxovanadate but appears to be a mixture of VO ₃ ⁺ (–546 ppm), VO³⁺ (–531 ppm) and VO ₂ ⁺ (–512 ppm), as shown by the⁵¹V-NMR spectrum. This reaction also occurred in phosphate-buffered medium but only on second addition of vanadyl. The compounds that stimulated the oxygen-consumption reaction were found to inhibit the oxygen-release reaction. A combination of these reactions occur depending on the proportion of the reactants (vanadyl and H₂O₂), the pH of the medium and the presence of some compounds that affect the secondary reactions.