The role of bisulfite in the debromination of 5-bromouracil. The debromination of 5-bromo-5,6-dihydrouracil-6-sulfonate

5-Bromouracil is dehalogenated in the presence of bisulfite buffers to yield uracil which subsequently adds bisulfite to form 5,6-dihydrouracil-6-sulfonate. Presumably, 5-bromo-5,6-dihydrouracil-6-sulfonate is an intermediate in uracil formation. Kinetic data indicate that the disappearance of 5-bromouracil in the presence of bisulfite buffers is second order with respect to total bisulfite concentration, thus indicating the participation of 2 moles of either sulfite or bisulfite in the overall reaction, Iodometric titrations of total bisulfite combined with spectral analysis of the various pyrimidine and dihydropyrimidine species present indicate that, in addition to the total bisulfite required to form 5,6-dihydrouracil-6-sulfonate, an additional mole of sulfite is consumed per mole of 5-bromouracil dehalogenated. These data combined with the finding that sulfate is generated during dehalogenation are indicative of a pathway for the dehalogenation of the intermediate 5-bromo-5,6-dihydro-uracil-6-sulfonate which involves the attack of sulfite either directly or via an intervening molecule of water to yield uracil. Subsequent reactions of halogen-containing intermediates yield sulfate and bromide as final products of the reaction.