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81.
S ummary : Cellvibrio fulvus and Sporocytophaga myxococcoides were grown on different types of cellulose fibres and the degradation was followed by means of light and electron microscopy. The very compact fibres prepared from cotton were degraded slowly by C. fulvus. The bacteria penetrated into the lumen of the fibres, accumulated there in large numbers, and degraded the fibres from within. Sporocytophaga myxococcoides attacked fibres both from the outside and from within by making close contact with the cellulose. Lignin free pulp fibres, which have a very open structure, were rapidly degraded by both kinds of bacteria. Cellvibrio fulvus also degraded these fibres from within. It is concluded that structure of the fibre greatly influences the rate at which different kinds of cellulolytio bacteria decompose cellulose.  相似文献   
82.
Proteins of the human erythrocyte membrane as modified by pronase   总被引:25,自引:0,他引:25  
Pronase degrades proteins on the outer surface of the human erythrocyte membrane which run in polyacrylamide-gel electrophoresis in the presence of sodium dodecyl sulfate at a molecular weight of approximately 125,000. Carbohydrate and sialic acid are removed, but fragments of molecular weight 50,000 to 100,000 remain attached to the membrane. The most prominent fragment, one of molecular weight about 73,000, can be labeled with a membrane-impermeable reagent (sulfanilic acid diazonium salt), so it is still accessible from the outside of the cell. Pronase rapidly inactivates membrane-bound acetylcholinesterase, but it has relatively little effect on the facilitated diffusion of glucose; both are inhibited by the diazonium salt. Extensive digestion leads to potassium loss and osmotic lysis. Ghosts prepared in 15 mosm-Tris (pH 7.6) are extensively degraded by pronase: essentially all the protein shifts to low molecular weight. Pronase is even more potent in 3% sodium dodecyl sulfate. Ghosts prepared from intact cells which have been treated with the enzyme hydrolyze when dissolved in the detergent unless steps are taken to inhibit proteolysis.  相似文献   
83.
Various auxotrophs are recovered from a penicillin enrichment cycle with differing efficiencies. Reconstruction experiments indicate that, under starvation conditions in the presence of penicillin, most auxotrophs undergo some death, whereas prolineless mutants are virtually immune to penicillin-induced killing.  相似文献   
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R A Berg  D J Prockop 《Biochemistry》1973,12(18):3395-3401
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1. (14)C from [1-(14)C]glucose injected intraperitoneally into mice is incorporated into glutamate, aspartate and glutamine in the brain to a much greater extent than (14)C from [2-(14)C]glucose. This difference for [1-(14)C]glucose and [2-(14)C]glucose increases with time. The amount of (14)C in C-1 of glutamate increases steadily with time with both precursors. It is suggested that a large part of the glutamate and aspartate pools in brain are in close contact with intermediates of a fast-turning tricarboxylic acid cycle. 2. (14)C from [1-(14)C]acetate and [2-(14)C]acetate is incorporated to a much larger extent into glutamine than into glutamate. An examination of the time-course of (14)C incorporated into glutamine and glutamate reveals that glutamine is not formed from the glutamate pool, labelled extensively by glucose, but from a small glutamate pool. This small glutamate pool is not derived from an intermediate of a fast-turning tricarboxylic acid cycle. 3. It is proposed that two different tricarboxylic acid cycles exist in brain.  相似文献   
89.
Escherichia coli PB160, which carries a tandem duplication with the gene order metB(+)argH(-)su(159) (+)thi(+): metB(+)argH(+)su(159) (-)thi(+), was used to study the mechanism of P1 transduction of genes in the duplicated region. Transduction of the su(159) (+) allele contained within the duplicated segment yields two kinds of su(159) (+) recombinants: 91% are haploid su(159) (+) and 9% are su(159) (+)/su(159) (-) merodiploids. The duplication in these merodiploid transductants includes the metB locus; however, both copies of the metB locus usually are derived from the recipient. Thus, the requirements for transduction of the "condition of merodiploidy" appear to be the cotransduction of the repeat point (the region where the duplication begins to repeat itself) and, of course, the selected marker (in this case su(159) (+)). A mechanism whereby two recipient chromosomes interact with the transduced "repeat point" region to regenerate the tandem duplication is implicated. It appears that a duplication much larger than the quantity of genetic material carried by a P1 phage can be produced in a transductant.  相似文献   
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