| Abstract: | Photon absorption by one of the roughly 200 chlorophylls of the plant Photosystem II (PSII) results in formation of an equilibrated excited state (Chl200*) and is followed by chlorophyll oxidation (formation of P680+) coupled to reduction of a specific pheophytin (Phe), then electron transfer from Phe− to a firmly bound quinone (QA), and subsequently reduction of P680+ by a redox-active tyrosine residue denoted as Z. The involved free-energy differences (ΔG) and redox potentials are of prime interest. Oxygen-evolving PSII membrane particles of spinach were studied at 5 °C. By analyzing the delayed and prompt Chl fluorescence, we determined the equilibrium constant and thus free-energy difference between Chl200* and the Z+,QA−] radical pair to be −0.43 ± 0.025 eV, at 10 μs after the photon absorption event for PSII in its S3-state. On basis of this value and previously published results, the free-energy difference between P680* and P680+,QA−] is calculated to be −0.50 ± 0.04 eV; the free-energy loss associated with electron transfer from Phe to QA is found to be 0.34 ± 0.04 eV. The given uncertainty ranges do not represent a standard deviation or likely error, but an estimate of the maximal error. Assuming a QA−/QA redox potential of −0.08 V Krieger et al., 1995, Biochim. Biophys. Acta 1229, 193], the following redox-potential estimates are obtained: +1.25 V for P680/P680+; +1.21 V for Z/Z+ (at 10 μs); −0.42 V for Phe−/Phe; −0.58 V for P680*/P680+. |
