Complete stoichiometry of free NADPH oxidation in liver microsomes

The stoichiometry of free NADPH oxidation in phenobarbital induced rabbit liver microsomes was measured by means of registering the rates of NADPH, H⁺ and O₂ consumption and $\text{O}{}_2{}^{\mathrm{<mtext>?</mtext>}}$ and H₂O₂ production. $\text{ΔO}{}_2{}^{\mathrm{<mtext>?</mtext>}}\text{:ΔH}{}_2\text{O}{}_2$ ratio is approximately I indicating that about half H₂O₂ results from $\text{O}{}_2{}^{\mathrm{<mtext>?</mtext>}}$ dismutation, the second half being formed directly. ΔNADPH:ΔH₂O₂ and ΔO₂:ΔH₂O₂ ratios exceed I and therefore another product of the reaction is water. The fact that the ratio (ΔNADPH-ΔH₂O₂):(ΔO₂-ΔH₂O₂) is 2 allows one to consider direct 4-electron O₂ reduction as the major way of water formation rather than endogenous substrate hydroxylation.