Eosin,a fluorescent probe of ATP binding to the (Na+ + K+)-ATPase

(1) Eosin bound to the $\text{(}\text{Na}{}^{\mathrm{+}}\text{+}\text{K}{}^{\mathrm{+}}\text{)-}\text{ATPase}$ in the presence of K⁺ has practically the same fluorescence as eosin without enzyme while in the presence of Na⁺ the fluorescence is higher, the excitation maximum is shifted from 518 to 524 nm, the emission maximum from 538 to 542 nm, and a shoulder appears at about 490 nm on the excitation curve. (2) The amount of eosin bound increases with the K⁺ concentration but with a low affinity. With equal concentrations of Na⁺ and K⁺ more is bound in the presence of Na⁺, and the difference between 150 mM Na⁺ and 150 mM K⁺ shows one high-affinity eosin binding site per ³²P-labelling site ($\text{K}{}_{\mathrm{D}}$ 0.45 μM). With lower concentrations of the cations there are between one and two Na⁺-dependent high-affinity eosin binding sites per ³²P-labelling site. (3) ATP (and ADP) prevents the hig-affinity Na⁺-dependent eosin binding and there is competition between eosin and ATP for the hydrolysis in the presence of Na⁺ (+Mg²⁺). (4) Eosin, like ATP, increases the Na⁺ relative to K⁺ affinity $\text{(}\text{Na}{}^{\mathrm{+}}\text{+}\text{K}{}^{\mathrm{+}}\text{= 150}\text{mM}$) for Na⁺ activation of hydrolysis and for Na⁺ protection against inactivation by $\text{N-}\text{ethylmaleimide}$. (5) The results suggest that the high affinity eosin binding site is an ATP binding site and that it is located on the enzyme in an environment with a low polarity, i.e., the conformational change induced by Na⁺ opens a high-affinity site for ATP while K⁺ closes the site (or decreases the affinity to a low level). The experiments suggest, furthermore, that the ATP which increases the Na⁺ relative to K⁺ affinity of the internal sites is not the ATP which is hydrolyzed, i.e., in a turnover cycle in the presence of $\text{Na}{}^{\mathrm{+}}\text{+}\text{K}{}^{\mathrm{+}}$ the system reacts with two different ATP molecules.